pattern printing using for loop
Asked on February 25, 2015
how to print the following pattern using single for loop?
1
12
123
1234
12345
1234
123
12
1
Replied on February 25, 2015
package programs;
public class ForLoopTest {
public static void main(String[] args) {
int i = 12345;
for(int j=4;j>-5;j--)
{
int p = i/(int)Math.pow(10,Math.abs(j));
System.out.println(p);
}
}
}
Replied on February 25, 2015
public void test() {
String template = "12345";
for (int i = 1; i < 10; i++) {
System.out.println(template.substring(0, i <= 5 ? i : 5 - (i - 5)));
}
}
or
public void test() {
String template = "12345";
for (int i = 4; i >= -4; i--) {
System.out.println(template.substring(0, 5 - Math.abs(i)));
}
}
Replied on February 25, 2015
1- using only a for loop (with no "hidden loop" such as substring)
2- which takes a parameter indicating the maximum number to print (contrary to the log10 based solutions)
3- in Java.
class loop1{
public static void main(String[] args) throws Exception {
printUpTo(5);
}
public static void printUpTo(int upperBound) {
int number = 1;
int nextNumber = 1;
for (int i = 0; i < upperBound * upperBound; i++) {
System.out.print(number);
if (number == nextNumber) {
if (i < (upperBound * upperBound / 2)) {
nextNumber++;
} else {
nextNumber--;
}
number = 1;
System.out.println();
} else {
number++;
}
}
}
}
